lxy/redkale
1
0
Fork 0
Code Issues Pull Requests Actions Packages Projects Releases Wiki Activity

删除append容易产生歧义的方法

Browse Source
This commit is contained in:
redkale
2023-06-12 12:54:38 +08:00
parent 3d379d59ef
commit 98f89d87d4
1 changed files with 0 additions and 37 deletions
Download Patch File Download Diff File Expand all files Collapse all files

37
src/main/java/org/redkale/util/Utility.java
View File

@@ -1349,43 +1349,6 @@ public final class Utility {
return news;
}
/**
* 将一个或多个新元素添加到数组结尾
*
* @param <T> 泛型
* @param one 单个对象
* @param objs 待追加数据
*
* @return 新数组
*/
public static <T> T[] append(final T one, final T... objs) {
if (one == null) {
return objs;
}
final T[] news = (T[]) Creator.newArray(one.getClass().getComponentType(), 1 + objs.length);
news[0] = one;
System.arraycopy(objs, 0, news, 1, objs.length);
return news;
}
/**
* 将一个或多个新元素添加到数组结尾
*
* @param <T> 泛型
* @param one 单个对象
* @param two 单个对象
* @param objs 待追加数据
*
* @return 新数组
*/
public static <T> T[] append(final T one, T two, final T... objs) {
final T[] news = (T[]) Creator.newArray(one.getClass().getComponentType(), 2 + objs.length);
news[0] = one;
news[1] = two;
System.arraycopy(objs, 0, news, 2, objs.length);
return news;
}
/**
* 将一个或多个新元素添加到数组结尾
*