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删除append容易产生歧义的方法

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redkale
2023-06-12 12:54:38 +08:00
parent 3d379d59ef
commit 98f89d87d4
1 changed files with 0 additions and 37 deletions
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37
src/main/java/org/redkale/util/Utility.java
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@@ -1349,43 +1349,6 @@ public final class Utility {
return news; return news;
} }
/**
* 将一个或多个新元素添加到数组结尾
*
* @param <T> 泛型
* @param one 单个对象
* @param objs 待追加数据
*
* @return 新数组
*/
public static <T> T[] append(final T one, final T... objs) {
if (one == null) {
return objs;
}
final T[] news = (T[]) Creator.newArray(one.getClass().getComponentType(), 1 + objs.length);
news[0] = one;
System.arraycopy(objs, 0, news, 1, objs.length);
return news;
}
/**
* 将一个或多个新元素添加到数组结尾
*
* @param <T> 泛型
* @param one 单个对象
* @param two 单个对象
* @param objs 待追加数据
*
* @return 新数组
*/
public static <T> T[] append(final T one, T two, final T... objs) {
final T[] news = (T[]) Creator.newArray(one.getClass().getComponentType(), 2 + objs.length);
news[0] = one;
news[1] = two;
System.arraycopy(objs, 0, news, 2, objs.length);
return news;
}
/** /**
* 将一个或多个新元素添加到数组结尾 * 将一个或多个新元素添加到数组结尾
* *